c^2+2c-80=0

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Solution for c^2+2c-80=0 equation: 


Simplifying
c2 + 2c + -80 = 0

Reorder the terms:
-80 + 2c + c2 = 0

Solving
-80 + 2c + c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(-10 + -1c)(8 + -1c) = 0


Subproblem 1
Set the factor '(-10 + -1c)' equal to zero and attempt to solve:

Simplifying
-10 + -1c = 0

Solving
-10 + -1c = 0

Move all terms containing c to the left, all other terms to the right.

Add '10' to each side of the equation.
-10 + 10 + -1c = 0 + 10

Combine like terms: -10 + 10 = 0
0 + -1c = 0 + 10
-1c = 0 + 10

Combine like terms: 0 + 10 = 10
-1c = 10

Divide each side by '-1'.
c = -10

Simplifying
c = -10

Subproblem 2
Set the factor '(8 + -1c)' equal to zero and attempt to solve:

Simplifying
8 + -1c = 0

Solving
8 + -1c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-8' to each side of the equation.
8 + -8 + -1c = 0 + -8

Combine like terms: 8 + -8 = 0
0 + -1c = 0 + -8
-1c = 0 + -8

Combine like terms: 0 + -8 = -8
-1c = -8

Divide each side by '-1'.
c = 8

Simplifying
c = 8
Solution
c = {-10, 8}

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